Question

The oxidation state of nitrogen in ammonia is molecule is -3
A) True
B) False

Answer 1

the nitrogen containing compounds have the tendency to have their oxidation states ranging from -3 to +5. The electronic configuration for the nitrogen is the following:
$1{{s}^{2}}2{{s}^{2}}2{{p}^{3}}$.

Complete answer:
The nitrogen tends to have 5 electrons in its valence shell and have three electrons present in its 2p orbital which are unpaired thus exhibiting paramagnetic nature. Nitrogen to obtain a stable configuration it either needs to lose all its 5 valence electrons from 2s and 2p orbital or gain 3 electrons in its 2p orbital.
Complete step by step answer: we need to calculate the oxidation state of nitrogen in ammonia to verify the given statement. So ammonia contains three atoms of hydrogen and one atom of nitrigen in it. So the oxidation state of hydrogen is considered as +1 so,

& x+3(1)=0 \\\ & x+3=0 \\\ & x=-3 \\\ \end{aligned}$$ So here we see that the oxidation state of nitrogen in ammonia is -3. Hence the statement given is absolutely correct. So the correct option is option ‘a’. Ammonia is an inorganic compound which has a pungent odour. It tends to undergo the process of self dissociation on dissolving in water. on the autoionization of the ammonia molecule the formation of conjugate base and conjugate acid takes place. **Hence, the correct option is (A) .** **Note:** the commercial method for the preparation of ammonia is Haber process. In this the direct combination of hydrogen and nitrogen takes place under high pressure and in the presence of a catalyst. It is used in fermentation, as a refrigerant and in manufacturing of various fertilizers.