Question

The oxidation state of molybdenum in its oxo complex species $\lbrack Mo_{2}O_{4}(C_{2}H_{4})_{2}(H_{2}O_{2})\rbrack^{2 -}$is

• A. +2
• B. +3
• C. +4
• D. +5

Answer 1

Answer: (B)

+3

Answer 2

: Oxidation number of Mo in

$\left\lbrack Mo_{2}O_{4}\left( C_{2}H_{4} \right)_{2}\left( H_{2}O_{2} \right) \right\rbrack^{2 -}$

2x + 4 (-2) + 0 + 0 = - 2

2x – 8 = -2 $\Rightarrow$ x = +3