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Question: The oxidation state of *Mn* in \(K_{2}MnO_{4}\) is...

The oxidation state of Mn in K2MnO4K_{2}MnO_{4} is

A
  • 2
B
  • 7
C

– 2

D
  • 6
Answer
  • 6
Explanation

Solution

K2MnO4K_{2}\underline{M}nO_{4} 2+x2×4=02 + x - 2 \times 4 = 0

x=82=+6x = 8 - 2 = + 6

So, oxidation state of Mn is +6.