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Question: The oxidation state of *Fe* in\(FeS_{2}\) is...

The oxidation state of Fe inFeS2FeS_{2} is

A

– 2

B
  • 2
C

0

D
  • 1
Answer
  • 2
Explanation

Solution

The structure of FeS2FeS_{2}is SFeS\begin{matrix} & & S \\ Fe & & \\ & & S \end{matrix}

Therefore FeS2FeS_{2}contain one per disulphide linkage, which is similar to that of peroxide linkages, having contribution of – 2 units towards the oxidation state

Let the oxidation state of Fe = x

\therefore x2=0x - 2 = 0 or x = 2

The oxidation state of Fe in FeS2FeS_{2}is + 2.