Question

The oxidation state of $Fe$ in the brown ring complex : $[Fe(H_2O)_5 NO]SO_4$ is

• A. 2
• B. 1
• C. 3
• D. 0

Answer 1

Answer: (B)

1

Answer 2

Let the oxidation state of $Fe$ in

$\left[ Fe \left( H _{2} O \right)_{5} NO \right] SO _{4}$ is $x$ .

$\left[ Fe \left( H _{2} O \right)_{5} NO \right]^{2+}$
$\Rightarrow \,\,\,\,\,\,x+0+1=2$
$\therefore\,\,\,\,\,\,x=+1$

Here $NO$ exists as nitrosyl ion $(NO^+)$