Question: The oxidation state of $Cr$ in $\lbrack Cr(NH_{3})_{4}Cl_{2}\rbrack^{+}$ is....

Question

The oxidation state of $Cr$ in $\lbrack Cr(NH_{3})_{4}Cl_{2}\rbrack^{+}$ is.

Answer 1

$\left\lbrack Cr(NH_{3})_{4}Cl_{2} \right\rbrack^{+}$

$x + 4 \times (0) - 2 = 1$ ⇒ $x + 0 - 2 = 1$

x = 1 + 2 = + 3.

Question: The oxidation state of \(Cr\) in \(\lbrack Cr(NH_{3})_{4}Cl_{2}\rbrack^{+}\) is....