Question

The oxidation state of Cr in $K_2Cr_2O_7$ is

• A. 5
• B. 3
• C. 6
• D. 7

Answer 1

Answer: (C)

6

Answer 2

Let the oxidation state of Cr is x
$K_2Cr_2O_7$
$\therefore$ 2 (+1) + 2x + 7(-2) = 0
2 + 2x - 14 = 0
2x - 12 = 0
2x = 12
x$= \frac {12}{2}=+6$