Question

The oxidation state of Cr in [Cr(NH3)4Cl2]+ is :

• A. 0
• B. +1
• C. +2
• D. +3

Answer 1

Answer: (D)

+3

Answer 2

[Cr(NH3)4Cl2]+ ; let the oxidation state of Cr is x, then x + 4 (–0) + 2 (–1) = +1

So, x = 3