Question

The oxidation state of Cr in $[Cr(NH_3)_4Cl_2]^+$ is :

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

Answer: (D)

3

Answer 2

$[Cr(NH_3)_4Cl_2]^+$ Let oxidation state of $Cr = x$ $NH_3 = 0$ $Cl =- 1$ Net charge $= + \,1$ $\therefore\quad\quad$ $[Cr(NH_3)_4Cl_2]^+$ $x + 4 \times 0 +2(-1)= + 1$ $\therefore\quad\quad x = 3$