Question

The oxidation numbers of hydrogen in $K H ,\, MgH _{2}$ and $NaH$ are respectively

• A. + 2, + 1 and - 2
• B. + 1, + 1 and + 1
• C. - 1, - 1 and - 1
• D. - 2, - 3 and - 1

Answer 1

Answer: (C)

- 1, - 1 and - 1

Answer 2

Hydrogen is present as hydride ion in these molecules i.e. Oxidation state is - 1.