Question

The oxidation number of sulphur in $S_8 , S_2F_2, H_2S$ respectively, are

• A. 0, +1 and -2
• B. +2, +1 and -2
• C. 0, +1 and +2
• D. -2, +1 and -2

Answer 1

Answer: (A)

0, +1 and -2

Answer 2

In S$_8$, oxidation number of S is 0, elemental state.
In S$_2F_2$, F is in - 1 oxidation state, hence S is in + 1 oxidation
state.
In H$_2$S, H is in +1 oxidation state, hence S is in - 2 oxidation
state.