Question

The oxidation number of sulphur in ${H2S2O7}$ is:

• A. 2
• B. 6
• C. 4
• D. 8

Answer 1

Answer: (B)

6

Answer 2

Oxidation no. of sulphur in ${H2S2O7}$ can be calculated as follows : 2 + 2x - 14 = 0 2x = 14 - 2 = 12 $x = \frac{12}{2} = 6$