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Question

Chemistry Question on Oxidation Number

The oxidation number of sulphur in H2SO4,H2S2O4andH2S2O6H_2SO_4, H_2S_2O_4 \, and \, H_2S_2O_6 are respectively

A

+3, +4, +5

B

+5, +4, +3

C

+6, +3, +5

D

+3, +5, +4

Answer

+6, +3, +5

Explanation

Solution

O.N. of S in H2SO4H_2SO_4: Let O.N. of S = x .-. 2 (+ 1) + x + 4(-2) = 0 x=+6\Rightarrow x=+6 O.N. of S in H2S2O4H_2S_2O_4 Let O.N. of S = x =2(4-1) + l x + 4(-2) = 0 x=+3\Rightarrow x=+3 O.N. of S in H2S2O6H_2S_2O_ 6 Let O.N. of S = x 2(4-1) + 2x + 6(-2) = 0 x=+5\Rightarrow x=+5