Question
Chemistry Question on Oxidation Number
The oxidation number of sulphur in H2SO4,H2S2O4andH2S2O6 are respectively
A
+3, +4, +5
B
+5, +4, +3
C
+6, +3, +5
D
+3, +5, +4
Answer
+6, +3, +5
Explanation
Solution
O.N. of S in H2SO4: Let O.N. of S = x .-. 2 (+ 1) + x + 4(-2) = 0 ⇒x=+6 O.N. of S in H2S2O4 Let O.N. of S = x =2(4-1) + l x + 4(-2) = 0 ⇒x=+3 O.N. of S in H2S2O6 Let O.N. of S = x 2(4-1) + 2x + 6(-2) = 0 ⇒x=+5