Question

The oxidation number of S in ${Na_2S_4O_6}$ is

• A. + 2.5 for each S atom
• B. + 2 and + 3 (two S have + 2 and other two have + 3)
• C. + 2 and + 3 (three S have + 2 and one S has + 3)
• D. + 5 and 0 (two S have + 5 and the other two have 0)

Answer 1

Answer: (D)

+ 5 and 0 (two S have + 5 and the other two have 0)

Answer 2

: The structure of ${Na_2S_4O_6}$ is The two S atoms which are linked to each other have O.N. of zero. The O.N. of other two S- atoms can be calculated as follows : 2x + 2 $\times$ 0 + 6 $\times$ -2 = -2 or 2 x = 12 ?