Question

The oxidation number of S in $H_{2}S_{2}O_{8}$is.

• A.
  • 2
• B.
  • 4
• C.
  • 6
• D.
  • 7

Answer 1

Answer: (C)

• 6

Answer 2

The chemical structure of $H_{2}S_{2}O_{8}$ is as follows:-

$H - O - \overset{\underset{O}{O}}{\overset{\underset{||}{||}}{S}} - O - O - \overset{\underset{O}{O}}{\overset{\underset{||}{||}}{S}} - O - H$

So the oxidation number of S should be :

$\underset{(\text{for}H)}{2 \times ( + 1)} + \underset{(\text{for}S)}{2 \times X} + \underset{(\text{for}O)}{6 \times ( - 2)} + \underset{(\text{for}O - O)}{2 \times ( - 1)} = 0$ or $X = + 6$.