Question

The oxidation number of phosphorus in Ba(H$_2PO_2 )_2$ is

• A. 3
• B. 2
• C. 1
• D. 4

Answer 1

Answer: (C)

1

Answer 2

In Ba(H$_2PO_2)_2$, oxidation number of Ba is +2. Therefore
$\, \, \, \, \, \, \, H_2PO_2^- : 2 \times (+1)+x+2 \times(-2)=-1$
\Rightarrow \hspace40mm x=+1