Question

The oxidation number of oxygen in $KO _{3}, Na _{2} O _{2}$ is

• A. 44622
• B. 1, 0
• C. 0, 1
• D. -0.33, -1

Answer 1

Answer: (D)

-0.33, -1

Answer 2

$KO _{3}$
Suppose O.N. of $O =x$
$+1+3 x =0$
$3 x =-1$
$x =-\frac{1}{3}$
$x =-0.33$
$Na _{2} O _{2}$
Suppose O.N. of $O =x$
$2 \times 1+2 x=0$
$2+2 x=0$
$2 x=-2$
$x=-\frac{2}{2}$
$x=-1$