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Question: The oxidation number of nitrogen in \((N_{2}H_{5})^{+}\)is...

The oxidation number of nitrogen in (N2H5)+(N_{2}H_{5})^{+}is

A

-2

B
  • 2
C

+3

D

-3

Answer

-2

Explanation

Solution

: (N2H5)+⇒2x+5=+1⇒2x=−4⇒\left( N_{2}H_{5} \right)^{+} \Rightarrow 2x + 5 = + 1 \Rightarrow 2x = - 4 \Rightarrow or, x = - 2