Question
Question: The oxidation number of N and Cl in \(\text{NOCl}{{\text{O}}_{\text{4}}}\) respectively are: A. +2...
The oxidation number of N and Cl in NOClO4 respectively are:
A. +2 and +7
B. +3 and +7
C. -3 and +5
D. +2 and -7
Solution
Think about the fixed oxidation numbers of certain atoms. Divide the given compounds into its constituent ions and then equate the charge with the oxidation states.
Complete answer:
First of all, we need to write the compound NOClO4 into its constituents in which they exist in the reactions. That is:
NOClO4→NO++ClO4−
Let’s find out the oxidation number of N inNO+.
We know that the fixed oxidation number of oxygen is -2. Since, the charge present on the ion is +1, the addition of the oxidation states of the atoms in the ion should result in +1.
Let, x be the oxidation state of N. Thus, the equation will be:
(1×x)+(1× oxidation state of O2)=1
Putting the values that we know: