Question
Question: The oxidation number of \(Mn\) in \(MnO_{4}^{- 1}\) is....
The oxidation number of Mn in MnO4−1 is.
A
- 7
B
– 5
C
- 6
D
- 5
Answer
- 7
Explanation
Solution
Mn shows + 7 oxidation state in MnO4−1
MnO4−1∗
x+(−2×4)=−1
x−8=−1
x=−1+8=+7.