Question

The oxidation number of Cr in $\lbrack Cr(NH_{3})_{6}\rbrack Cl_{3}$ is.

• A. 8
• B. 6
• C. 4
• D. 3

Answer 1

Answer: (D)

3

Answer 2

$x + 6 \times (0) + 3 \times ( - 1) = 0$

$\mathbf{x - 3 = 0}$, $\mathbf{x = + 3,}$ Oxidation number of $Cr$ is $= + 3.$