Question

The oxidation number of carbon in ${CH_2O}$ is

• A. -2
• B. 2
• C. 0
• D. -4

Answer 1

Answer: (C)

0

Answer 2

Let $x$ be the oxidation number of $C$ in $CH _{2} O$. Then $x+2(+1)+(-2)=0$ $x+2-2=0$ $x=0$