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Question

Chemistry Question on Oxidation Number

The oxidation number of C in sucrose C12H22O11C_{12}H_{22}O_{11} is

A

4

B

3

C

2

D

Zero

Answer

Zero

Explanation

Solution

Let O.N. of C in C12H22O11C_{12}H_{22}O_{11} =12×x+22+11(2)=0,x=012 \times x+22+11(-2)=0,x=0