Question
Chemistry Question on Oxidation Number
The oxidation number of C in sucrose C12H22O11 is
A
4
B
3
C
2
D
Zero
Answer
Zero
Explanation
Solution
Let O.N. of C in C12H22O11 =12×x+22+11(−2)=0,x=0
The oxidation number of C in sucrose C12H22O11 is
4
3
2
Zero
Zero
Let O.N. of C in C12H22O11 =12×x+22+11(−2)=0,x=0