Question

The oxidation number of C in $CH_4, CH_3Cl. CH_2Cl_2, CHCl_3 \,and \,CCl_4$ is respectively

• A. 4, - 2, 0, + 2, + 4
• B. #ERROR!
• C. 4, 2, 0, - 2, - 4
• D. 0, 2, - 2, 4, 4

Answer 1

Answer: (A)

4, - 2, 0, + 2, + 4

Answer 2

$CH_4; x+4(-1) = 0 \,or \,x = +4$ $H_3C1; x + 3( + 1) + (-1)= 0 \,or\,x = -2$ $CH_2C1_2$ given in Q-6$CHC1_3$;x + 1 + 3(-1) = 0 or x = + 2$CCI_t4$; x + 4(-1) = 0 or x = +4.