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Question

Chemistry Question on Oxidation Number

The oxidation number of Ag in Tollen's reagent is

A

0

B

1

C

2

D

1.5

Answer

1

Explanation

Solution

Tollen's reagent is [Ag(NH3)2]OH[Ag(NH_3)_2]OH Let O.N. of Ag = xx \therefore x+2(0)=1x + 2 (0) = 1 or xx = 1