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Question: The outside air temperature is \[30^\circ F\], what is the temperature in Kelvin?...

The outside air temperature is 30∘F30^\circ F, what is the temperature in Kelvin?

Explanation

Solution

Temperature is a physical number that describes how hot or cold something is. When a body comes into contact with another that is colder or hotter, it is the manifestation of thermal energy, which is present in all matter and is the cause of the occurrence of heat, a flow of energy. A thermometer is used to determine the temperature. Thermometers are calibrated in a variety of temperature scales that have traditionally defined temperature using a variety of reference points and thermometric substances.

Formula used
T(∘F)  =  T(K)  × 95 − 459.67{T_{(^\circ F)}}\; = \;{T_{(K)}}\; \times {\text{ }}\dfrac{9}{5}{\text{ }} - {\text{ }}459.67
T(∘F){T_{(^\circ F)}}= Temperature in Fahrenheit
T(K){T_{(K)}}= Temperature in Kelvin

Complete step by step answer:
The Fahrenheit scale is a temperature scale based on Daniel Gabriel Fahrenheit (1686–1736), a scientist who established it in 1724. The unit is the degree Fahrenheit (symbol: ∘F^\circ F). There are several stories of how he created his scale in the beginning, but the original article says that the lowest defining point, 0 ∘F0{\text{ }}^\circ F, was set as the freezing temperature of a brine solution formed from water, ice, and ammonium chloride (a salt).
Water has a melting point of 32∘F32^\circ F and a boiling temperature of 212∘F212^\circ F on the Fahrenheit scale (at standard atmospheric pressure). Water's boiling and freezing points are 180 degrees apart as a result of this. The kelvin is the SI's (International System of Units) basic unit of temperature, denoted by the letter K.
Now T(∘F)  =  T(K)  × 95 − 459.67{T_{(^\circ F)}}\; = \;{T_{(K)}}\; \times {\text{ }}\dfrac{9}{5}{\text{ }} - {\text{ }}459.67
Given T(∘F){T_{(^\circ F)}}=30∘F30^\circ F
Substituting the values
30  =  T(K)  × 95 − 459.6730\; = \;{T_{(K)}}\; \times {\text{ }}\dfrac{9}{5}{\text{ }} - {\text{ }}459.67
489.67=  T(K)  × 95 489.67 = \;{T_{(K)}}\; \times {\text{ }}\dfrac{9}{5}{\text{ }}
TK=489.67×59{T_K} = \dfrac{{489.67 \times 5}}{9}
TK=272.04K{T_K} = {\text{272}}{\text{.04K}}

Note: A temperature in degrees Fahrenheit is supplied to us, and we must convert it to Kelvin. Another method for converting a temperature value from degrees Fahrenheit to Kelvin is to convert it to degrees Celsius first, then to Kelvin directly. The kelvin is a unit of measurement for light sources' colour temperature.