Question

The osmotic pressure of a dilute solution is $7 × 10^5$ Pa at $273K$. Osmotic pressure of the same solution at$283K$ is _____$× 10^4 Nm^2$

Answer 1

The osmotic pressure ($\pi$) is given by the formula:

$\pi = CRT$

Since concentration (C) and R are constants, we can use the ratio:

$\frac{\pi_1}{\pi_2} = \frac{T_1}{T_2}$

Rearranging to find $\pi_2$:

$\pi_2 = \pi_1 \cdot \frac{T_2}{T_1} = 7 \times 10^5 \times \frac{283}{273}$

Calculating $\pi_2$:

$\pi_2 = 72.56 \times 10^4 \, \text{Nm}^{-2}$

Thus, the osmotic pressure at 283 K is approximately:

So, the correct answer is: 72.56 or 73