Question

The orthocentre of triangle formed by lines

$4x - 7y + 10 = 0,$ $x + y = 5$ and $7x + 4y = 15$ is.

• A. (1, 2)
• B. (1, –2)
• C. (–1, –2)
• D. (–1, 2)

Answer 1

Answer: (A)

(1, 2)

Answer 2

Orthocentre of right angled triangle is same as the vertex of right angle. Therefore, point of intersection of $7 x + 4 y - 15 = 0$ and $4 x - 7 y + 10 = 0$ is (1, 2).