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Question: The order of the differential equation of all parabolas, whose latus rectum is 4a and axis parallel ...

The order of the differential equation of all parabolas, whose latus rectum is 4a and axis parallel to the x axis is

A

one

B

four

C

three

D

two

Answer

two

Explanation

Solution

The general equation of a parabola whose axis is parallel to the x-axis is given by:

(yk)2=4A(xh)(y - k)^2 = 4A(x - h)

where (h,k)(h, k) is the vertex of the parabola and 4A4A is the length of the latus rectum.

According to the problem statement, the latus rectum of the parabolas is 4a4a. This means 4A=4a4A = 4a, where 'a' is a given constant (a fixed length). Therefore, the equation of the family of parabolas becomes:

(yk)2=4a(xh)(y - k)^2 = 4a(x - h)

In this equation, hh and kk are arbitrary constants because they can vary for different parabolas within this family (different vertices). The value 'a' is a fixed parameter defining the latus rectum length, not an arbitrary constant that varies from one member of the family to another.

The order of a differential equation is equal to the number of independent arbitrary constants in the general solution (or the equation of the family of curves). In the given equation (yk)2=4a(xh)(y - k)^2 = 4a(x - h), there are two independent arbitrary constants: hh and kk.

Therefore, the order of the differential equation for this family of parabolas will be 2.