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Question

Chemistry Question on Order of Reaction

The order of a reaction with rate equal to kCA3/2CB1/2kC_A^{3/2} C_B^{-1/2} is

A

1

B

12-\frac{1}{2}

C

32-\frac{3}{2}

D

2

Answer

1

Explanation

Solution

Given, r = kCA3/2CB1/2kC_A^{3/2} C_B^{-1/2}
\therefore \, \, Order of reaction = 32+(12)\frac{3}{2} + \big(-\frac{1}{2}\big)
\hspace25mm = \frac{3-1}{2} = 1