Question
Chemistry Question on Order of Reaction
The order of a reaction with rate equal to kCA3/2CB−1/2 is
A
1
B
−21
C
−23
D
2
Answer
1
Explanation
Solution
Given, r = kCA3/2CB−1/2
∴ Order of reaction = 23+(−21)
\hspace25mm = \frac{3-1}{2} = 1