Question

The order ionization energies of different orbital is

• A. $s>\,p>\,d>\,f$
• B. $p>\,d>\,s>\,f$
• C. $f >\, d>\, p>\,s$
• D. $s=p=d=f$

Answer 1

Answer: (A)

$s>\,p>\,d>\,f$

Answer 2

In a multielectron atoms, the probability of finding an electron near the nucleus follows the order, s-electrons >$\,$ p-electrons > $\,$d-electrons > $\,$f-electrons. So, the s-electrons are more closer to the nucleus and are held more tightly than p-electrons and so on. As a result ionization energies follow the order : s >$\,$p >$\,$ d >$\,$ f.