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Question: The order in which the reagent must be used to separate the compound I - IV is : <img src="https://...

The order in which the reagent must be used to separate the compound I - IV is :

A

NaOH, NaHCO3, HCl

B

HCl, NaOH, NaHCO3

C

NaHCO3, NaOH, HCl

D

NaOH, HCl, NaHCO3

Answer

NaHCO3, NaOH, HCl

Explanation

Solution

II is soluble in NaHCO3, I is soluble in NaOH and III is soluble in HCl.