Solveeit Logo

Question

Question: The order and degree of the differential equation \(\frac { d ^ { 2 } y } { d x ^ { 2 } } = \sqrt {...

The order and degree of the differential equation

d2ydx2=1+(dydx)2\frac { d ^ { 2 } y } { d x ^ { 2 } } = \sqrt { 1 + \left( \frac { d y } { d x } \right) ^ { 2 } }is

A

4, 2

B

1, 2

C

2, 2

D
Answer

2, 2

Explanation

Solution

Given equation can be written as

(d2ydx2)2=1+(dydx)2\left( \frac { d ^ { 2 } y } { d x ^ { 2 } } \right) ^ { 2 } = 1 + \left( \frac { d y } { d x } \right) ^ { 2 }

Hence order is 2 and degree is 2.