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Question: The order and degree of the differential equation \(\rho = \frac { \left[ 1 + \left( \frac { d y } ...

The order and degree of the differential equation

ρ=[1+(dydx)2]3/2d2y/dx2\rho = \frac { \left[ 1 + \left( \frac { d y } { d x } \right) ^ { 2 } \right] ^ { 3 / 2 } } { d ^ { 2 } y / d x ^ { 2 } } are respectively

A

2, 2

B

2, 3

C

2, 1

D

None of these

Answer

2, 2

Explanation

Solution

ρd2ydx2=[1+(dydx)2]3/2\rho \cdot \frac { d ^ { 2 } y } { d x ^ { 2 } } = \left[ 1 + \left( \frac { d y } { d x } \right) ^ { 2 } \right] ^ { 3 / 2 }(ρd2ydx2)2=[1+(dydx)2]3\left( \rho \cdot \frac { d ^ { 2 } y } { d x ^ { 2 } } \right) ^ { 2 } = \left[ 1 + \left( \frac { d y } { d x } \right) ^ { 2 } \right] ^ { 3 }

Order = 2, degree = 2