Question

The orbital velocity of electron in the ground state of hydrogen is v. If the electron is excited to energy state – 0.54 eV, its orbital velocity will be –

• A. v
• B. $\frac{v}{3}$
• C. $\frac{v}{5}$
• D. $\frac{v}{7}$

Answer 1

Answer: (C)

$\frac{v}{5}$

Answer 2

E = – 13.6eV$\frac{1^{2}}{n^{2}}$= – 0.54eV

̃ n = 5 ̃ v_n = $\frac{c}{137}$.$\frac{Z}{n}$ = $\frac{c}{137} \cdot \frac{1}{5} = \frac{v}{5}$s