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Question: The orbital velocity of an artificial satellite in a circular orbit just above the earth's surface i...

The orbital velocity of an artificial satellite in a circular orbit just above the earth's surface is v. For a satellite orbiting at an altitude of half of the earth's radius, the orbital velocity is

A

32v\frac { 3 } { 2 } v

B

32v\sqrt { \frac { 3 } { 2 } } v

C

23v\sqrt { \frac { 2 } { 3 } } v

D

23v\frac { 2 } { 3 } v

Answer

23v\sqrt { \frac { 2 } { 3 } } v

Explanation

Solution

v=GMR+hv = \sqrt { \frac { G M } { R + h } }

For first satellite h=0h = 0, v1=GMRv _ { 1 } = \sqrt { \frac { G M } { R } }

For second satellite h=R2h = \frac { R } { 2 },

v2=2GM3Rv _ { 2 } = \sqrt { \frac { 2 G M } { 3 R } }

v2=23v1=23vv _ { 2 } = \sqrt { \frac { 2 } { 3 } } v _ { 1 } = \sqrt { \frac { 2 } { 3 } } v