Question
Question: The orbital diagram in which the Aufbau principle is violated is:  rule, where the sum of the principal (n) and azimuthal quantum numbers (l) tells us the energy level of the orbital.
3.Lower (n+l) values correspond to lower orbital energies. But in case two orbitals share equal (n+l) values, the orbital having lower n value is said to have lower energy associated with it.
4.The order we follow to fill the orbital with electrons is: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, and so on.
Now, if we look at the options, we can see that we are provided with 2s and 2p orbitals. So, as per Aufbau principle, first electrons are filled in 1s orbital. Since s electrons can occupy a maximum of two electrons, once it is filled with two electrons, the third one enters in 2s orbital as per sequence of increasing energy levels. It can also accommodate two electrons.
Once it is completely filled by two electrons, the next energy level is 2p orbital which can accommodate 6 electrons. We know that 2px,2py,2pz are the degenerate orbitals and thus have the same energy levels. So, the electrons can occupy either of three in any order. In this way, filing of orbitals goes on as per Aufbau principle.
No, looking at the option give, we can easily find out that Aufbau principle is violated in the option C as 2s is not completely filled, yet electrons are filled in 2p orbital which has higher energy than 2s. and we already know that 2s must be completely filled by two electrons followed by the 2p orbital as per Aufbau rule.
Hence, the correct option is (C).
Note: The electron configuration of chromium is an exception due to several factors such as the increased stability provided by half-filled subshells and the relatively low energy gap between the 3d and the 4s subshells. Due to this 3d orbital is completely filled first followed by 4s. Similarly, in copper due to the stability provided by a completely filled 3d subshell.