Question

The orbital angular momentum of an electron in 2s-orbital is :

• A. $+ \frac{1}{2}\frac{h}{2\pi}$
• B. Zero
• C. $\frac{h}{2\pi}$
• D. $\sqrt{2}\frac{h}{2\pi}$

Answer 1

Answer: (B)

Zero

Answer 2

Orbital angular momentum $= \sqrt { \ell ( \ell + 1 ) } \frac { \mathrm { h } } { 2 \pi } = 0$ (since $\ell$ = 0 for s orbital).