Question

The orbital angular momentum of an electron in $2s$ -orbital is

• A. $+\frac{1}{2}\frac{h}{2\pi }$
• B. zero
• C. $\frac{h}{2\pi }$
• D. $\sqrt{2}\frac{h}{2\pi }$

Answer 1

Answer: (B)

zero

Answer 2

Orbital angular momentum
$=\sqrt{l(l+1)} \cdot \frac{h}{2 \pi}$
for $2 s$-orbital, $l=0$
$\therefore$ Orbital angular momentum
$=\sqrt{0(0+1)} \frac{h}{2 \pi}$
$=$ zero