Question

The orbital angular momentum of a p-electron is given as

• A. $\frac{h}{\sqrt{2}\pi}$
• B. $\sqrt{3} \frac{h}{2 \pi}$
• C. $\sqrt{\frac{3}{2}} \frac{h}{\pi}$
• D. $\sqrt{6} \frac{h}{2 \pi}$

Answer 1

Answer: (A)

$\frac{h}{\sqrt{2}\pi}$

Answer 2

Orbital angular momentum $(m)$
$= \sqrt{l(l+1)} \frac{h}{2 \pi}$
For $p$-electron; $l = 1$
Thus, $m = \sqrt{1\left(1+1\right)} \frac{h}{2\pi}= \frac{\sqrt{2}h}{2\pi} = \frac{h}{\sqrt{2}\pi}$