Question

The orbital angular momentum of a 4d electron will be:

• A. $\frac{4h}{2\pi}$
• B. $\frac{\sqrt{6}h}{2\pi}$
• C. $\frac{\sqrt{6}h}{4\pi}$
• D. $\frac{\sqrt{2}h}{4\pi}$

Answer 1

Answer: (B)

$\frac{\sqrt{6}h}{2\pi}$

Answer 2

The correct option is (B) $\frac{\sqrt{6}h}{2\pi}$
For d-orbital, l=2
where
l=Azimuthal quantum number
Orbital angular momentum is given by L=$\frac{h}{2\pi}\sqrt{l(l+1)}$
Putting the value of l, we get
L=$\frac{h}{2\pi}\sqrt{2}(2+1)$=$\frac{\sqrt{6}h}{2\pi}$