Question

The orbital angular momentum for an electron revolving in an orbit is given by$\sqrt{\mathcal{l}\left( \mathcal{l} + 1 \right)}\frac{h}{2\pi}$

This momentum for an s-electron will be given by

• A. $+ \frac{1}{2}\frac{h}{2\pi}$.
• B. Zero
• C. $\frac{h}{2\pi}$
• D. $\sqrt{2}\frac{h}{2\pi}$

Answer 1

Answer: (B)

Zero

Answer 2

The value of $\mathcal{l}$ (azimuthal quantum number) for s -electron is equal to zero.

Orbital angular momentum $= \sqrt{\mathcal{l}\left( \mathcal{l} + 1 \right)}.\frac{h}{2\pi}$

Substituting the value of l for s-electron $\sqrt{0(0 + 1)}.\frac{h}{2\pi} = 0$