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Question: The opposite vertices of a square are (1, 2) and (3, 8), then the equation of a diagonal of the squa...

The opposite vertices of a square are (1, 2) and (3, 8), then the equation of a diagonal of the square passing through the point (1, 2), is.

A

3xy1=03 x - y - 1 = 0

B

3yx1=03 y - x - 1 = 0

C

3x+y+1=03 x + y + 1 = 0

D

None of these

Answer

3xy1=03 x - y - 1 = 0

Explanation

Solution

Slope =8231=3= \frac { 8 - 2 } { 3 - 1 } = 3.

The diagonal isy2=3(x1)3xy1=0y - 2 = 3 ( x - 1 ) \Rightarrow 3 x - y - 1 = 0.