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Question: The operating magnetic field for accelerating protons in a cyclotron oscillator having frequency of ...

The operating magnetic field for accelerating protons in a cyclotron oscillator having frequency of 12 MHz is

and 1 Me V

= 1.6×10−131.6 \times 10 ^ { - 13 }J

A

0.69 T

B

0.19 T

C

0.59 T

D

0.49 T

Answer

0.19 T

Explanation

Solution

=2×3.14×1.67×10−27×12×1061.6×10−19=0.79 T= \frac { 2 \times 3.14 \times 1.67 \times 10 ^ { - 27 } \times 12 \times 10 ^ { 6 } } { 1.6 \times 10 ^ { - 19 } } = 0.79 \mathrm {~T}