Question

The $[ OH ]^{-}$in a solution is $1\, mol\, L ^{-1}$. The $pH$ of the solution is

• A. 1
• B. 0
• C. 14
• D. $10^{-14}$

Answer 1

Answer: (C)

14

Answer 2

Given, $\left[ OH ^{-}\right]=1\, mol\, L^{-1}$
So, we know that
$p O H=-\log \left[O H^{-}\right]$
$p O H=-\log 1=0$
$\because p H +p O H=14$
$\therefore p H=14-0=14$