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Question: The [OH–] in 100.0 ml of 0.016 M-HCl (aq) is :...

The [OH–] in 100.0 ml of 0.016 M-HCl (aq) is :

A

5 × 1012 M

B

3 × 10–10 M

C

6.25 × 10–13 M

D

2.0 × 10–9 M.

Answer

6.25 × 10–13 M

Explanation

Solution

[H+] = 0.016 M

[H+] [OH–] = 10–14

⇒\Rightarrow [OH–] = 100×10−1616×10−3\frac{100 \times 10^{- 16}}{16 \times 10^{- 3}} = 6.25 × 10–13 M