Question

The $O-H$ bond length in ${{H}_{2}}O$ is $x{{A}^{0}}.$ The $O-H$ bond length in ${{H}_{2}}{{O}_{2}}$ is:
(A) $(B)$ x{{A}^{0}} $(C)$ >x{{A}^{0}} $(D)$ 2x{{A}^{0}} $

Answer 1

Hint : We know that the average length between the nuclei of two bound atoms in a molecule is known as bond length or bond distance in molecular geometry. It's a property of a bond between fixed-type atoms that can be transferred, despite the rest of the molecule being largely unaffected.

Complete Step By Step Answer:
As we know, the most basic form of peroxide is hydrogen peroxide oxygen-oxygen single bond. It's a colorless substance that's used in aqueous solutions to keep things clean. It is used as a disinfectant as well as a bleaching agent. In rocketry, concentrated hydrogen peroxide is used as a propellant because it is a highly reactive oxygen species. The distance between the nuclei of two chemically bound atoms in a molecule is measured by bond length. It is roughly proportional to the number of the two bonded atoms' covalent radii.
Bond length is proportional to bond order: the longer the bond, the more electrons involved in its creation. Bond length is also inversely related to bond strength and bond dissociation energy: a stronger bond would be shorter if all other variables remain constant. Half of the bond width is equal to the covalent radius in a bond between two similar atoms. It's a colorless liquid that's used in aqueous solutions to keep things safe. It is used as a disinfectant as well as a bleaching agent. In solid phase $O-H$ bond length in ${{H}_{2}}{{O}_{2}}$ ​ is $98.8$ pm and in gaseous phase it is $95$ pm. But $O-H$ bond length in water is always $96$ pm.
Therefore, the correct answer is option A.

Note :
Remember that the bond length is inversely proportional to bond order in covalent bonds; higher bond orders result in stronger bonds, which are followed by stronger forces of attraction that tie the atoms together. These powerful powers of attraction result in short bonds.