Question

The numerical value of charge on either plate of capacitor C shown in figure

• A. $CE$
• B. $\frac{C E R_{1}}{-R_{1}+\gamma_{-}}$
• C. $\frac{C E R_{2}}{R_{2}+r}$
• D. $\frac{C E R_{1}}{R_{2}+q_{-}}$

Answer 1

Answer: (B)

$\frac{C E R_{1}}{-R_{1}+\gamma_{-}}$

Answer 2

$R_{\text {total }}=R_{1}+r$
(Since capacitor is a DC blocking element)
$V=i R_{1} V=\frac{E R_{1}}{R_{1}+r}\left(\because i=\frac{E}{R_{1}+r}\right)$
Since, $q=C V$
$\Rightarrow q=\frac{C E R_{1}}{R_{1}+r}$