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Question

Chemistry Question on Equilibrium

The numbers of H+ {H^+} ions present in 1 mL of a solution whose pH is 13

A

6.022×10106.022 \times 10^{10}

B

6.022×1076.022 \times 10^{7}

C

6.022×10206.022 \times 10^{20}

D

6.022×10236.022 \times 10^{23}

Answer

6.022×1076.022 \times 10^{7}

Explanation

Solution

pH= 13?
⇒    [H]+=10−13 mol L−1\Rightarrow \:\:\:\: {[H]^+ = 10^{-13} \, mol \, L^{-1}}
⇒\Rightarrow 1000 ml solution contains
10−13×6.022×1023 H+ ions{ 10^{-13} \times 6.022 \times 10^{23} \, H^+ \, ions}
=6.022×1010H+ ions= 6.022 \times 10^{10} {H^+ \, ions}
∴   \therefore \:\:\: 1 ml solution contains
6.022×10101000H+ions\frac{6.022 \times 10^{10}}{1000} {H^+ ions}
=6.022×107 H+ions= 6.022 \times 10^7 \, {H^+ ions}