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Question

Question: The numbers \(3\), \(5\), \(6\) and \(4\) have frequencies of \(x\), \(x + 2\), \(x - 8\) and \(x + ...

The numbers 33, 55, 66 and 44 have frequencies of xx, x+2x + 2, x8x - 8 and x+6x + 6 respectively. If their mean is 44 then the value of xx is
A) 55
B) 66
C) 77
D) 44

Explanation

Solution

Here we are given that the numbers have required frequencies respectively. In this problem we are going to find the value of xx with the use of given frequency values. And also here students learn to calculate mean value from the frequency values.

Formula used: Mean =Sum of the product of frequencies and the given numbers  Sum of the frequencies\dfrac{{{\text{Sum of the product of frequencies and the given numbers }}}}{{{\text{ Sum of the frequencies}}}}

Complete step-by-step solution:
That is, Mean (X)\left( {\overline X } \right)= fxn\dfrac{{\sum {fx} }}{n}
If the given number xx has frequency ff then their product is fxfx
Given that the numbers 33,55,66 and 44 have frequencies of xx, x+2x + 2, x8x - 8 and x+6x + 6 respectively.
The number 33 has frequency xx then fxfx=3x3x
The number 55 has frequency xx+22 then fxfx=5x5x+1010
The number 66 has frequency xx88 then fxfx=6x6x4848
The number 44 has frequency xx+66 then fxfx=4x4x+2424
Now, Mean (X)\left( {\overline X } \right)=3x+5x+10+6x48+4x+24x+x+2+x8+x+6\dfrac{{3x + 5x + 10 + 6x - 48 + 4x + 24}}{{x + x + 2 + x - 8 + x + 6}}
(X)\left( {\overline X } \right)=18x144x\dfrac{{18x - 14}}{{4x}}
Mean =44 is given
Therefore 44=18x144x\dfrac{{18x - 14}}{{4x}}
Cross multiply the equation, we get
\Rightarrow 44×4x4x=18x18x1414
\Rightarrow 16x16x=18x18x1414
Take the xx terms into one side.
\Rightarrow 16x16x18x18x=−1414
Subtracting the terms,
\Rightarrow2x2x=−1414
Simplifying we get,
\Rightarrow xx=142\dfrac{{ - 14}}{{ - 2}}
Solving we get,
\Rightarrow xx=77
Therefore the value of xx is 77

Option C is the correct answer.

Note: To calculate the mean of grouped data, the first step is to determine the midpoint of each interval. These midpoints must then multiply by the frequencies of the corresponding classes. The sum of the products divided by the total number of values will be the value of the mean.